How do you find the zeros of the function f(x)= x^2-2x-4?

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The zeros of this office are ##x_1=1-sqrt(5)## and ##x_2=1+sqrt(5)##

To confront the zeros of a quadratic office you original enjoy to reckon ##Delta##. In this fact it is ##Delta = (-2)^2-4*1*(-4) = 20## ##Delta > 0 ## so office has 2 authentic zeros which can be reckond using:

##x_1=(-b-sqrt(Delta))/(2a)## and ##x_2 = (-b+sqrt(Delta))/(2a)##

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